Question

The quantity (7^3*4^6*5^7*6^2) *(7^2*4^8*5^5*6^3) will end in how many zeros

Answer 1

12 zeros. 4^6*5^6=6 zeroes

5*6^2=1 zero

4^5*5^5=5 zeroes

6+1+5=12

Answer 2

Answer:

Step-by-step explanation: