Question

The quantity of charge in the units of faraday required to convert two mole of Fe2O3 to Fe is

Answer 1

Answer: 6F

Explanation:

no of moles = it/nF

n= 3 as it changes from Fe3+ to Fe

2=it/3F

6=it/F

it/F = amount of charge in Faraday

Answer 2

To find:

Quantity of charge in the units of faraday required to convert two mole of $Fe_{2}O_{3}$ to Fe?

Calculation:

First of all, let's write the half cell reaction:

• In $Fe_{2}O_{3}$, iron has +3 valency.

$Fe^{+3} + 3e^{-}\rightarrow Fe$

From the half reaction we can say:

• 3 moles of electrons (i.e. 3 F of electricity is needed) to produce 1 mole of Fe.

Now, for 2 moles of Fe to be produced, we need:

$= 2 \times 3$

$= 6 \: moles \: of \: electrons$

$= 6 \: F \: electricity$

So, 6F electricity is needed.