Question

The quantity of charge liberated during the
formation of 3.6 grams of water in hydrogen
fuel cell is
​

Answer 1

Answer:

Explanation:

Gram atomic mass of water (H2O) = (1×2+16) gm = (2+16) gm = 18 gm

∴ Number of molecules in 18 gm of water = 1 mol

∴ Number of molecule in 1 gm of water = 1/18 mol

∴ Number of molecule in 3.6 gm of water = (1/18 x 3.6)mol = 0.2 mol

Thanks for reading :-)