Question

The quantity of Dextrose required to prepare 500 ml
2% solution is​

Answer 1

Answer:

Assuming that is 2.5% (w/v) then that is 2.5 grams dextrose per 100 mls of solution. Since you want 250 mls of solution, you need:

2.5 g/100 ml x 250 ml = 6.25 grams of dextrose required.

Explanation:

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Answer 2

The quantity of Dextrose required to prepare 500 ml 2 % solution is ...

solution : concentration of solution 2 % in 500 ml solution.

i.e., percentage concentration = mass of dextrose/volume of solution × 100

⇒2 % = x/500 × 100

⇒x = 10 g

Therefore the mass of dextrose is 10 g

[note : chemical formula of dextrose is C₆H₁₂O₆

so molecular mass of dextrose = 6 × atomic mass of C + 12 × atomic mass of H + 6 × atomic mass of O

= 6 × 12 + 12 × 1 + 6 × 16

= 72 + 12 + 96

= 180 g/mol ]