Question

The quantity of electricity (in Faraday) required to completely reduce 0.2 mol Mno4- to Mn2+ ions is

Answer 1

Hello dear,

● Answer = 1 F

● Explaination-
# Given-
n = 0.2 mol

# Solution-
Charge on Mn in MnO4-,
q1 = -1 - 4(-2)
q1 = -1+8
q1 = +7

Charge on Mn in Mn2+,
q2 = +2

Difference in charge,
Q = q1-q2 = 7 - 2 = 5 F

But for 0.2 moles,
Electricity required will be
Q' = n × Q
Q' = 0.2 × 5
Q' = 1 F.

Electricity required in reduction reaction is 1 F.

Answer 2

Answer:0.6 F

Explanation:

Shown in photo