Question

The quantity of electricity required to completely reduce 0.2 mol of MnO4- into MnO2 is

Answer 1

Answer:

HEY

Explanation:

• MARK MY ANSWER AS BRAINLIEST
• MARK MY ANSWER AS EXCELLENT
• MARK MY ANSWER AS RATE AND THANK MY ANSWER
• THANK YOU
• PLEASE FOLLOW ME

UR ANSWER IS : OPTION B

#96500C#

Answer 2

Given:

Moles of Mno4 = 02.

To Find:

Quantity of electricity required to reduce it to Mno2.

Solution:

in MnO4, charge of Mn will be =

q1 = -1 - 4(-2)

q1 = 7

In Mno2, charge on Mn will be

q2 = 2

Difference in charge = Q = q1 - q2

= 7 - 2

= 5

Since, we have 0.2 moles, electricity -

Q = n × Q

Q = 0.2 × 5

Q = 1 F.

Since 1F = 96,500 ( Faraday's law)

Thus,

0.2 F = 96,500

F = 19300

Answer: The electricity needed for reduction is 19300F.