The quantity of heat which can rise the temperature of x gm of a substance through t10C can rise the temperature of y gm of water through t20C is same. The ratio of specific heats of the substance to motor is
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Given:
Temperature that can rise x = t10C
Temperature that can rise y = t20C
To Find:
Ratio of specific heats of the substance to motor is
Solution:
For substance x -
ΔQ = ms1 ΔT= x × s1 × t1 --- eq 1
For substance y -
ΔQ = ms2 ΔT= y × s2 × t2 --- eq 2
From equation 1 and 2
x × s1 × t1 = y × s2 × t2
s1/s2 = yt2/xt1 ( Also represents the water equation)
where, s1 is the specific heat of substance and s2 is the specific heat of water
Answer: The ratio of specific heats of the substance to motor is yt2/xt1
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