the quantity of pcl5 was heated in a 10 dm3 vessel at 250 d, pcl5=pcl3+cl2.
at equilibrium the vessel contain 0.1 mole of pcl5 and 0.2 mole of cl2. calculate the equilibrium constant
Answers
Explanation:
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Question - A quantity of PCl5 was heated in a 10 litre vessel at 250°C ; PCl5(g) ⇌ PCl3(g) + Cl2(g). At equilibrium the vessel contains 0.1 mole of PCl5 0.20 mole of PCl3 and 0.2 mole of Cl2. Calculate the equilibrium constant of the reaction
Given - Volume of vessel - 10 dm³
Number of moles - 0.2 mole of PCl3 and Cl2 and 0.1 mole of PCl5.
Find - Equilibrium constant for the given reaction.
Solution - The formula to calculate equilibrium constant of the reaction is - Kc = [PCl3] [Cl2]/[PCl5].
The concentration of PCl5 is - 0.1/10 = 0.01 mol/dm³
The concentration of PCl3 is - 0.2/10 = 0.02 mol/dm³
The concentration of Cl2 is - 0.2/10 = 0.02 mol/dm³
Keeping the values in equation-
Kc = 0.02*0.02/0.01
Kc = 0.04
Hence, the equilibrium constant of the reaction is 0.04.