Question

The quantity of pure NaOh will be required to neutralize completely 50 ml n/10 h2so4​

Answer 1

Answer:

Firstly,write the equation

H2SO4 + 2NaOH → Na2SO4 + 2H2O

We have 50 mL (0.050 L ) of 1 N NaOH. That’s 0.050 L x 40 gm/L = 2.0 gm NaOH

Then solve the proportion

x gm H2SO4/ 98 = 2.0 gm NaOH / 80

x /98 = 2/80

x = 2.45 gm H2SO4