Physics, asked by madhurayadiyal210, 2 months ago

The quantity x depends on a, b as x = 2a²/b.If error in measurement of a, b is 1% and 2% respectively, then error in measurement of x, is
(1)2%
(2)3%
(3)4%
(4)2.5%​

Answers

Answered by rajarshiranjan238
2

Answer:

4%

Explanation:

Hey, This one is so simple.

%error of x= 2×% error in a+ %error in b=2×1% +2%= 2%+2% = 4%.

Hope you will get the benefit.

Mark answer as the brainliest if you like to do so.

Answered by RvChaudharY50
2

Given :- The quantity x depends on a, b as x=2a^2/b If error in measurement of a, b is 1% and 2% respectively, then error in measurement of x, is ?

Solution :-

we have,

→ x = 2a²/b

so,

→ ∆x/x = [2 *(∆a/a) + ∆b/b ]

given that, error in measurement of a, b is 1% and 2% respectively . so,

  • ∆a/a = 1%
  • ∆b/b = 2%

putting both values we get,

→ ∆x/x = [ 2 * 1 + 2 ]

→ ∆x/x = (2 + 2)

→ ∆x/x = 4 % (Option 3)

therefore, the % error in measurement of x is 4% .

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