Question

The quantum number of four electrons are given below:
I. n = 4, l = 2, mₗ = -2, mₛ = -1/ 2
II. n = 3, l = 2, mₗ = 1, mₛ = +1/ 2
III. n = 4, l = 1, mₗ = 0, mₛ = +1/ 2
IV. n = 3, l = 1, mₗ = 1, mₛ = -1/ 2
The correct order of their increasing energies will be:
(A) I < III < II < IV (B) I < II < III < IV
(C) IV < II < III < I (D) IV < III < II < I

Answer 1

Answer:

answer is option (B)

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Answer 2

Higher the value of (n + l)  Higher will be energy of orbital. If (n + l) are equal, then higher the value n higher will be energy