The quantum of energy carried by a single photon of 6x1014 frequency is: 1) 1.98*10-16 2) 2.98x10-19 J 3) 3.98x10-19 J 4) 4.98x10-16 J
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3) 3.98 × 10⁻¹⁹ J
Explanation:
Given: ν = 6 × 10¹⁴, h = 6.626 × 10⁻³⁴, E = ?
Energy of photon = E = hν
= 6.626 × 10⁻³⁴ × 6 × 10¹⁴
= 3.98 × 10⁻¹⁹ J
Hence option 3 is the correct.
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