The quantumyield for decomposition of HI is 0.2 . In an experiment 0.01 moles of HI are decomposed . Find the no. of protons absorbed.
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Please find below the solution to the asked query:
As we know that, in 1 mole of HI we have 6.022 x 1023 number of HI molecules, then in 0.01 mole of HI we will have = 6.022 x 1023 x 0.01 = 6.022 x 1021 numbers of HI molecules.
As quantum yield = Molecules decomposed / photon absorbed
photon absorbed = Molecules decomposed /quantum yield = 6.022 x 1021 / 0.2 = 3.011 x 1022
Hope this information will clear your doubts about Structure of Atom.
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Please find below the solution to the asked query:
As we know that, in 1 mole of HI we have 6.022 x 1023 number of HI molecules, then in 0.01 mole of HI we will have = 6.022 x 1023 x 0.01 = 6.022 x 1021 numbers of HI molecules.
As quantum yield = Molecules decomposed / photon absorbed
photon absorbed = Molecules decomposed /quantum yield = 6.022 x 1021 / 0.2 = 3.011 x 1022
Hope this information will clear your doubts about Structure of Atom.
If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.
Best Wishes !
Was this answer helpful
mark me brainliest if you liked it
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