the ques is 6th one.........plzzz ans fast its urgent.....plzzzz
Attachments:
TheRuhanikaDhawan:
Please mention if you need the calculations and the method to get the answer, otherwise people won't understand. Thanks!
Ok...thaxxxx
Answers
Answered by
1
case : 1
car travels a distance of 30km at speed of 60km/ hr
speed =60km/hr
distance = 30km
let time be t1
t1= dist/ speed
= 30/60
=1/2 hours
casec2 :
speed = 40km/ hr
distance = 30km
time t2 = distance/ speed
= 30/40
3/4 hrs
total time = t1+ t2
1/2 + 3/4
= 5/4 hrs
average speed = total distance/ total time
= 30+30) *4/5
= 48km/ h
car travels a distance of 30km at speed of 60km/ hr
speed =60km/hr
distance = 30km
let time be t1
t1= dist/ speed
= 30/60
=1/2 hours
casec2 :
speed = 40km/ hr
distance = 30km
time t2 = distance/ speed
= 30/40
3/4 hrs
total time = t1+ t2
1/2 + 3/4
= 5/4 hrs
average speed = total distance/ total time
= 30+30) *4/5
= 48km/ h
Similar questions