the question in above I can't solve pls any have answere
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Answered by
1
r1:r2=1:2
r1=x
r2=2x
h1:h2=2:1
h1=2y
h2=y
ratio of theri volume=
![(\pi {r1}^{2} h1) \div \pi {r2}^{2} h2 \\ \frac{ {x}^{2} \times 2y}{ {(2x)}^{2} y} \\ \frac{2 {x}^{2} y}{4 {x}^{2} y} \\ \frac{1}{2} (\pi {r1}^{2} h1) \div \pi {r2}^{2} h2 \\ \frac{ {x}^{2} \times 2y}{ {(2x)}^{2} y} \\ \frac{2 {x}^{2} y}{4 {x}^{2} y} \\ \frac{1}{2}](https://tex.z-dn.net/?f=%28%5Cpi+%7Br1%7D%5E%7B2%7D+h1%29+%5Cdiv+%5Cpi+%7Br2%7D%5E%7B2%7D+h2+%5C%5C++%5Cfrac%7B+%7Bx%7D%5E%7B2%7D++%5Ctimes+2y%7D%7B+%7B%282x%29%7D%5E%7B2%7D+y%7D++%5C%5C++%5Cfrac%7B2+%7Bx%7D%5E%7B2%7D+y%7D%7B4+%7Bx%7D%5E%7B2%7D+y%7D++%5C%5C+++%5Cfrac%7B1%7D%7B2%7D+)
r1=x
r2=2x
h1:h2=2:1
h1=2y
h2=y
ratio of theri volume=
shahidkhanjr:
tnks
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0
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