The question in which two equal chords are given and to find angle abc
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Triangle AOB as two sides with the same length, [AO] and [OB]. Thus the angles OAB and OBA, opposite, are equals. Since angle AOB=70 degrees, the other two are half the remaining, 55 degrees.
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Consider the triangles ΔAOB and ΔCOD,
OA = OC and OB = OD (Since they are the radii of the circle)
AB = CD (As given in the question)
So, by SSS congruency, ΔAOB ≅ ΔCOD
∴ By CPCT we have,
∠AOB = ∠COD. (Hence proved).
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