Question

the question is 3(x-4)+2(4n-5)=5(n+2)+16​

Answer 1

3(x-4)+2(4n-5)=5(n+2)+16

3x -12 + 8n - 10 = 5n +10 + 16

3x - 22 +3n - 26 =0

3x -48 +3n=0

Answer 2

Answer:

3(x-4)+2(4n-5)= 5(n+2)+16

3x-12+8n-10= 5n+10+16

3x-12-10+8n= 5n+16

3x-2+8n=5n+16

3x+8n-5n= 16+2

3x-3n= 18

3(x-n)= 18

x-n=18/3

x-n= 6

x= 6+n