Math, asked by janesh1, 9 months ago

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Answered by sandy1816
1

Step-by-step explanation:

LHS

1/cosecA-cotA - 1/sinA

=sinA/1-cosA - 1/sinA

=sin²A-(1-cosA)/sinA(1-cosA)

=sin²A-1+cosA/sinA(1-cosA)

=1-cos²A-1+cosA/sinA(1-cosA)

=cosA(1-cosA)/sinA(1-cosA)

=cotA

RHS

1/sinA-1/cosecA+cotA

=1/sinA-sinA/1+cosA

=1+cosA-sin²A/sinA(1+cosA)

=1+cosA-1+cos²A/SinA (1+cosA)

=cosA(1+cosA)/sinA(1+cosA)

=cotA

LHS=RHS

Answered by MяMαgıcıαη
2

Answer:

in the LHS multiplying and dividing by cosec @ + cot@

and in rhs multiplying and dividing by cosec @- cot @ ( @ is theta)

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