Question

the question is ( Bansi has 3 times as many two - rupee coins as he has five rupee coins , if he has in all sum of rupees 77 , how many coins of each denomination does he have ?? ( can you give the explanation very clearly showing the working too)

Answer 1

Answer:

7,21

Step-by-step explanation:

Let the number of 5 rupee coins = x

It is given that,

he has 3 times as many as 2 rupee coins as he has five rupee coins => 5x + 2(3x).

Sum of rupees = 77

So the equation can be written as,

5x + 2(3x) = 77

=> 11x = 77

=> x = 7

Then,

3x = 21

Thus,

Number of 5 rupee coins = 7

Number of 2 rupee coins = 21

Hope it helps!