Question

The question is based on probabilities from tabled data. Please download the attachment to view the question.

9071254d451d53fa2652fc73ce15a9df.docx

Answer 1

Relative frequency of 
A = 0.25
B = 0.35
C = c
D = 0.275

Sum of relative frequencies = 1
⇒ 0.25+0.35+0.275+c = 1
⇒ 0.875 + c = 1
⇒ c = 1 - 0.875
⇒ c = 0.125

frequency of C = 40
let total frequency = x
then 0.125 × x = 40
⇒ 0.125x = 40
⇒ x = 40/0.125 = 320

frequency of A = 0.25×320 = 80
frequency of B = 0.35×320 = 112
frequency of A = 0.275×320 = 88

See the complete table in the attachment.

Answer 2

plzz see the attachment for the answer

dc34d04ca008eb24d4a9e709034d42ae.docx