Question

the Question is:Find x,y,z in the given parallelogram ABCD​

Answer 1

Step-by-step explanation:

y=45°(Alternate angle)

z=180°-70°. (Opposite angles of a parallelogram

z=angleCBA are equal)

z=110°

In Triangle ABC, By angle sum property of triangle

angle A+angle B+angle C=180°

x+y+angleCBA=180°

45°+y+110°=180°

y+155°=180°

y=25°

Answer 2

Question:-

Find x,y,z in the given parallelogram ABCD

_______________________________

Solution:-

Value of z:-

<z=<CBA. (Opposite angels of parallelogram are equal)

therefore,

<CBA=180°-70°

=110°.

Value of x:-

<x=<DCA. (Alternate Interior angel)

therefore,

<DCA=180°-(45°+110°)

=180°-155°

=25°

Value of y:-

<y=<DAC=45°

<y=45°