Question

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Answer 1

Answer: (a) 0 is correct answer

$\int \frac{dx}{\sqrt{2ax-x^2} } \\\\\implies \int \frac{dx}{2ax-x^2+a^2-a^2}\\\\ \implies \int \frac{dx}{a^2-(a^2+x^2-2ax)}\\\\ \implies \int \frac{dx}{a^2-(x-a)^2} \\\\\implies sin^{-1}(\frac{x-a}{a} )$

Now comparing this equation with

$a^n.sin^{-1}(\frac{x-a}{a} )$,

we get ,

$a^n=1\\\\\implies a^n=a^0\\\\\implies n=0$

                                         

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Answer 2

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