Math, asked by Anonymous, 11 months ago

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Answered by anjiisuhag

1

Answer:

ur statement is wrong

Step-by-step explanation:

at the place of sin2 or cos2 u should use sin3 and cos3, then the answer is possible .

I think I'm right..

Answered by Anonymous

2

$\huge\blue{Answer}$

$<body bgcolor ="r"> <font color =pink>$ (sinθ- 2 sin^3θ)/(2cos^3θ-cosθ)

=sinθ(1-2sin^2θ)/cosθ(2cos^2 θ-1)

= sin θ [1- 2(1- cos^2 θ)/cos θ(2cos ^2 θ -1)

= sin θ [1-2+ 2cos ^2 θ]/ cos θ (2 cos^2θ -1)

= sin θ(2cos^2 θ -1)/ cos θ(2 cos ^2θ-1)

= sin θ/ cos θ

= tanθ

$<marquee><font color= "red">$ Hope it helps you mark as brainliest please

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