Question

the question is in the attachment

Answer 1

Answer :-

• 30 is the answer.

Given :-

X = 16 and Y = 9

Find :-

$\rm(\sqrt{x + y})^{2} - \sqrt{x} + y = ?$

Solution :-

Here , we need just to put the value of x and y and then we need to simply .

Let's do :-

$\rm\hookrightarrow (\sqrt{16 + 9}) ^{2} - \sqrt{16} \: + 9$

$\rm\hookrightarrow (\sqrt{4 \times 4 +3 \times 3}) ^{2} - \sqrt{4 \times 4} \: + 9$

$\rm\hookrightarrow (4 +3 ) ^{2} - 4 \: + 9$

$\rm\hookrightarrow ({4 ^{2} +3 ^{2} }) - 4 \: + 9$

$\rm\hookrightarrow ({4 \times 4 +3 \times 3}) - 4 \: + 9$

$\rm\hookrightarrow 16 +9 - 4 \: + 9$

$\rm\hookrightarrow \bf 30 \: \star$

$\therefore \rm \: \bf30 \: is \: the \: answer$

Answer 2

Solution :-

→ √(x + y)² - √x + y

putting given values of x = 16 and y = 9 we get,

→ √(16 + 9)² - √16 + 9

→ √(25)² - √16 + 9

using √(a)² = a ,

→ 25 - √16 + 9

taking positive values ,

→ 25 - 4 + 9

→ 34 - 4

→ 30 (Ans.)

taking negative values,

→ 25 - (-4) + 9

→ 25 + 4 + 9

→ 38 (Ans.)

Learn more :-

Let a, b and c be non-zero real numbers satisfying (a³)/(b³ + c³) + (b³)/(c³ + a³) + (c³)/(a³ + b³)

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if a²+ab+b²=25

b²+bc+c²=49

c²+ca+a²=64

Then, find the value of

(a+b+c)² - 100 = __

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