Question

The Question is in the attachment.

$\bf {Class\:X}$
$\bf {Chapter:\:Circles}$​

Answer 1

Answer : 55°

Given :

Angle AOB = 125°

To find : Angle COD

Solution :

We know that,

The Opposite sides of a quadrilateral ABCD circumscribing circle, subtend supplementary angles at the centre O.

Thus,

Angle AOB + Angle COD = 180°

125° + Angle COD = 180°

Angle COD = 55°

Thus, Answer : 55°.

Answer 2

Solution:-

Given:-

• ∠AOB = 125°

To Find:-

• ∠ COD = ?

Find:-

We know that,

Opposite side of the Quadrilateral circumscribing a circle substend a Supplementary angle.

=) ∠AOB + ∠COD = 180°

=) ∠COD = 180° - 125°

=) ∠COD = 55°

Hence,

∠COD = 55°.