the question is in the given picture
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the value of x for above equation is 2
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x^2 -4ax +4a^2 - b^2 = 0
= x^2 -2.2a.x +(2a)^2 -b^2 =0
= (x-2a)^2 - b^2 = 0
= (x-2a+b)(x-2a-b) = 0
Hence, x= 2a-b
or. x=2a +b
= x^2 -2.2a.x +(2a)^2 -b^2 =0
= (x-2a)^2 - b^2 = 0
= (x-2a+b)(x-2a-b) = 0
Hence, x= 2a-b
or. x=2a +b
minu08:
thank u so much!!
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