Question

the question is-
$2x - 5y + 4 = 0 \\ 2x + y - 8 = 0$

Answer 1

Hey mate..

Given ,

2x - 5y + 4 = 0-------(1)

2x + y - 8 = 0----------(2)


Now, we subtract Eq.(1) from Eq.(2) to get ,

( 2x + y - 8 ) - ( 2x - 5y + 4 ) = 0

=> 2x + y - 8 - 2x + 5y - 4 = 0

=> 6y - 12 = 0

=> 6y = 12

=> y = 12 / 6

Thus ,

y = 2........(3)

Putting the value of Eq.(3) in Eq.(1) to get ,

2x - 5(2) + 4 = 0

=> 2x - 10 + 4 = 0

=> 2x - 6 = 0

=> 2x = 6

=> x = 6 / 2

Thus ,

x = 3

We have,

Required values of x and y are 3 and 2 respectively.


#racks.

Answer 2

therefore X=3, Y=2 THIS IS THE SOLUTION