Question

the question number is 14&15

Answer 1

14.
area of circle pi r^2
2x22/7xr^2=308
r=7
perimeter 2x(l+b)
let d of circle + d of circle2
d=14 so l of rectangle =28 and b=d=14
then now substitute then area will be 84


15. =area of bigger semicircle-smaller semicircle
=1/2xpixr1^2-1/2xpixr2^2
=57.75

here r1=7,r2=3.5 (since o is a mid point)