The question of this figure
In the adjoining figure, SP and RQ are perpendicular on the same line PQ. Prove that ΔPQS is congruent to ΔQPR
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<QPS = <PQR ( perpendicular )
SP = QR ( 5cm )
PQ = QA ( common line )
so ∆PQS = ∆QPR ( by SAS congress criteria )
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It will help you
It can also be done by RHS because you 90° ,Hypotenuse and Side is also there.
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