Math, asked by ishita42572, 1 year ago

The question starts from Solve:

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Answered by Srejoye1934
1

 \frac{ {6x}^{2}  + 13x - 4}{2x  + 5}  =  \frac{ {12x}^{2} + 5x - 2}{4x + 3}  \\  {24 {x}^{3} +  {52x}^{2}  - 8x  +  {18x}^{2} + 39x - 12 } =  {24x}^{3}  +  {10x}^{2} - 4x +  {60x}^{2}   + 25x - 10 \\  {70x}^{2}  + 31x - 12 =  {70x}^{2}  + 21x - 10 \\ 31x - 21x =  12 - 10 \\ 10x = 2 \\ x =  \frac{1}{5}

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