Question

The quotient becomes 3 and remainder is 10 when we divide a certain number by 34. What is the number?​

Answer 1

Answer:

112

Step-by-step explanation:

according to division algorithm

dividend =quotient * divisor + remainder

dividend=3*34+10=102+10=112

Answer 2

Answer:

The number which is divide by $34$ for which quotient becomes $3$ and  leaves a remainder $10$ is $112$.

Step-by-step explanation:

Recall the divisional algorithm,

$a=bq+r$, where $a$ is dividend, $b$ is divisor, $q$ is quotient and $r$ is remainder.

Given: quotient, $q=3$

remainder, $r=10$

divisor, $b=34$

Let the number (dividend) be $a$.

Then by divisional algorithm,

$a=bq+r$

Substitute the values of $b, q$ and $r$ as follows:

⇒ $a=34(3)+10$

⇒ $a=102+10$

⇒ $a=112$

Therefore, the number is $112$.

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