Question

the quotient of two integers is -5 if one of the integers is 10 what are the possible value of the other number?​

Answer 1

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The division operation is performed on two integers, so the result is an integer. The fact that you assign it to a double afterwards doesn't change that.

What you're doing in your question, with the implicit conversions made explicit, is

int A = 1;

int B = 2;

double C = (double) (A / B);

However, if you want to perform the division operation using doubles you have to explicitly cast at least one of the operands to double:

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Answer 2

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• The division operation is performed on two integers, so the result is an integer. The fact that you assign it to a double afterwards doesn't change that.
• The division operation is performed on two integers, so the result is an integer. The fact that you assign it to a double afterwards doesn't change that.What you're doing in your question, with the implicit conversions made explicit, is
• The division operation is performed on two integers, so the result is an integer. The fact that you assign it to a double afterwards doesn't change that.What you're doing in your question, with the implicit conversions made explicit, isint A = 1;
• The division operation is performed on two integers, so the result is an integer. The fact that you assign it to a double afterwards doesn't change that.What you're doing in your question, with the implicit conversions made explicit, isint A = 1;int B = 2;
• The division operation is performed on two integers, so the result is an integer. The fact that you assign it to a double afterwards doesn't change that.What you're doing in your question, with the implicit conversions made explicit, isint A = 1;int B = 2;double C = (double) (A / B);
• The division operation is performed on two integers, so the result is an integer. The fact that you assign it to a double afterwards doesn't change that.What you're doing in your question, with the implicit conversions made explicit, isint A = 1;int B = 2;double C = (double) (A / B);However, if you want to perform the division operation using doubles you have to explicitly cast at least one of the operands to double:

Answer 3

$\huge \star{\underline{\mathtt{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}} \star$

• The division operation is performed on two integers, so the result is an integer. The fact that you assign it to a double afterwards doesn't change that.
• The division operation is performed on two integers, so the result is an integer. The fact that you assign it to a double afterwards doesn't change that.What you're doing in your question, with the implicit conversions made explicit, is
• The division operation is performed on two integers, so the result is an integer. The fact that you assign it to a double afterwards doesn't change that.What you're doing in your question, with the implicit conversions made explicit, isint A = 1;
• The division operation is performed on two integers, so the result is an integer. The fact that you assign it to a double afterwards doesn't change that.What you're doing in your question, with the implicit conversions made explicit, isint A = 1;int B = 2;
• The division operation is performed on two integers, so the result is an integer. The fact that you assign it to a double afterwards doesn't change that.What you're doing in your question, with the implicit conversions made explicit, isint A = 1;int B = 2;double C = (double) (A / B);
• The division operation is performed on two integers, so the result is an integer. The fact that you assign it to a double afterwards doesn't change that.What you're doing in your question, with the implicit conversions made explicit, isint A = 1;int B = 2;double C = (double) (A / B);However, if you want to perform the division operation using doubles you have to explicitly cast at least one of the operands to double: