Question

The r.m.s. value of an a.c. of 50 Hz is 10 A.
The time taken by the alternating current in
reaching from zero to maximum value and the
peak value of current will be
1) 2x10 sec and 14.14 A 2) 1x10-sec and 7.07 A
3) 5x10 sec and 7.07 A 4) 5x10 sec and 14.14 A​

Answer 1

Answer: t = 5 x 10^-3 sec. &

Peak current = 14.14 A

Detailed solution is in the attachment.

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