Question

the ra
Q13. The height of water level is a tank is H= 96 cm. Find
range of water stream coming out of a hole at
depth H/4 from upper surface of water.​

Answer 1

Solution:

As per the given data,

• The height of the water level in the tank (H) = 96 m
• The distance of the hole from the upper surface(h) = H/4 = 96/4 = 24 m.

We need to find the range of the water stream.

Range of the water stream is given by,

$\implies\sf{R = \sqrt{H(H-h)} }$  

here,

• H = height of the water level in the tank
• h = distance of the hole from the upper surface

Now let's substitute the values,

$\implies\sf{R = \sqrt{96(96 -24 )} }$

$\implies\sf{R = \sqrt{96(72 )} }$

$\implies\sf{R = \sqrt{6912} }$

$\implies\boxed{\sf{R = 83.13 m }}$

The range of the water stream is 83.13 m.