Question

The race track is in the form of a ring whose inner circumference and outer circumference are 352 m

and 396 m. Find the width of the track.​

Answer 1

Answer:

Step-by-step explanation:

Let the radius of inner track =r

2πr=352

2×  

7

22

​  

×r=352

r=56

let the radius of outer track =R

2πR=396

2×  

7

22

​  

×R=396

R=63

width of track= radius of outer track−radius of inner track

=63−56=7m

Answer 2

Answer:

44m

Step-by-step explanation:

Given

inner circumference = 352m

outer circumference = 396m

.'. required width = 396 - 352

= 44m