the racetrack is in the form of ring whose inner circumference is 352 M and Outer circumference is 396 M find the width of track
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Width of Track = Radius of Outer Track - Radius of Inner Track
Outer track = 2 *22/7 * R = 396
= R = 396*7 / 2*22 = 2772 / 44 = 63 M
Inner Track = 2 * 22/7 * r = 352 m
= r = 352 * 7 / 22 *2 = 2464 / 44 = 56m
Therefore width og=f the track = R - r = 63 - 56 = 7 m
Therefore width of the track is 7 m
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Cheers!!
Outer track = 2 *22/7 * R = 396
= R = 396*7 / 2*22 = 2772 / 44 = 63 M
Inner Track = 2 * 22/7 * r = 352 m
= r = 352 * 7 / 22 *2 = 2464 / 44 = 56m
Therefore width og=f the track = R - r = 63 - 56 = 7 m
Therefore width of the track is 7 m
Hope it helps !!
Cheers!!
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