the radical centre of the circle
- 1)2+(y-2)2 = 341, (x-4)2 + (y - 1)2 = 341
X - 5)2+(y - 4)2=341 is
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Answer:
s1:(x−1)2+(y−2)2=341⇒x2+y2−2x−4y+5=341
s2:(x−4)2+(y−1)2=341⇒x2+y2−8x−2y+17=341
s3:(x−5)2+(y−4)2=341⇒x2+y2−10x−8y+41=341
Radical axis of s1 and s2 is s1−s2=0
6x−12−2y=0−−(1)
Radical axis of s1 and s3 is s1−s3=0
8x−4
Step-by-step explanation:
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Answered by
1
Step-by-step explanation:
Answer:
s1:(x−1)2+(y−2)2=341⇒x2+y2−2x−4y+5=341
s2:(x−4)2+(y−1)2=341⇒x2+y2−8x−2y+17=341
s3:(x−5)2+(y−4)2=341⇒x2+y2−10x−8y+41=341
Radical axis of s1 and s2 is s1−s2=0
6x−12−2y=0−−(1)
Radical axis of s1 and s3 is s1−s3=0
8x−4
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