Math, asked by dhamangavevaishu, 6 months ago

the radical centre of the circle
- 1)2+(y-2)2 = 341, (x-4)2 + (y - 1)2 = 341
X - 5)2+(y - 4)2=341 is

Answers

Answered by saishshetty2008
1

Answer:

s1:(x−1)2+(y−2)2=341⇒x2+y2−2x−4y+5=341

s2:(x−4)2+(y−1)2=341⇒x2+y2−8x−2y+17=341

s3:(x−5)2+(y−4)2=341⇒x2+y2−10x−8y+41=341

Radical axis of s1 and s2  is  s1−s2=0

6x−12−2y=0−−(1)

Radical axis of s1 and s3 is s1−s3=0

8x−4

Step-by-step explanation:

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Answered by manvitha7876
1

Step-by-step explanation:

Answer:

s1:(x−1)2+(y−2)2=341⇒x2+y2−2x−4y+5=341

s2:(x−4)2+(y−1)2=341⇒x2+y2−8x−2y+17=341

s3:(x−5)2+(y−4)2=341⇒x2+y2−10x−8y+41=341

Radical axis of s1 and s2  is  s1−s2=0

6x−12−2y=0−−(1)

Radical axis of s1 and s3 is s1−s3=0

8x−4

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