the radii of both uniformly charge ring and a sphere is R both have a charge q in them the centre of the sphere is located on the axis of the ring and is at a distance of Rx312
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Here OBO
1
and OAO
1
will make two equilateral triangle because the sides are equal length of radius r. Thus <BOA=60
o
+60
o
=120
o
This is the one-third angle of circular ring (360). So charge enclosed by sphere will be Q/3.
By Gauss's law, the flux ϕ=
ϵ
0
Q
en
=
3ϵ
0
Q
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