Question

the radii of circle ends of a bucket of height =24cm are 15 cm and 5cm . find the area of its curved surface

Answer 1

Radius of top of the bucket ( R ) = 15 cm.


Radius of bottom of the bucket ( r ) = 5 cm.


And


Height of the bucket ( H ) = 24 cm.





Therefore,


Slant Height ( L ) = √ ( H )² + ( R - r )²



=> ✓ ( 24)² + ( 15 - 5 )²



=> √576 + (10)²



=> √ 576 + 100


=> √676



=> 26 cm.

• Curved Surface area of bucket = πL ( R + r ) cm².



=> 22/7 × 26 ( 15 + 5 ) cm².




=> ( 22 × 26 ) × 20 / 7 cm².



=> ( 22 × 26 × 20 ) / 7 cm².




=> 1634.28 cm².

Answer 2

Answer:

1634.3 cm² .

Step-by-step explanation:

Let radii be R and r .

It is given R = 15 cm , r = 5 cm and h = 24 cm

We know slant height :

l = [ √ h² + ( R - r )² ]

l = √ 24² + 10²

l = 26 cm .

Now ,

C.S.A. = π ( R + r ) l

= 3.14 × 20 × 26 cm²

= 1634.3 cm² .