Question

The radii of circular ends of a bucket of height 24 cm are 15 cm and 5 cm. Find the area of its curved surface.

Answer 1

Given,
height of bucket , h = 24cm
radius of circular ends of bucket are 5cm and 15cm
Let, $r_1=5cm,r_2=15cm$
then, slant height of bucket is given by ,
$l=\sqrt{h^2+(r_2-r_1)^2}$
$l=\sqrt{24^2+(15-5)^2}=\sqrt{676}=26cm$

now, curved surface area of bucket is given by,
$A=\pi(r_1+r_2)l$

or, A = π(15 + 5) × 26

or, A = π × 20 × 26

or, A = 520π cm²

hence, curved surface area of bucket is 520π cm²

Answer 2

Answer:

1634.3 cm² .

Step-by-step explanation:

Let radii be R and r .

It is given R = 15 cm , r = 5 cm and h = 24 cm

We know slant height :

l = [ √ h² + ( R - r )² ]

l = √ 24² + 10²

l = 26 cm .

Now ,

C.S.A. = π ( R + r ) l

= 3.14 × 20 × 26 cm²

= 1634.3 cm² .