The radii of circular ends of a bucket of height 24 cm are 15 cm and 5 cm. Find the area of it curved surface.
Answers
Answered by
6
Answer:
1634 cm²
Step-by-step explanation:
Find the slanted height:
(15 - 5)² + (24)² = c²
c² = 676
c = 26 cm
The length of the slanted height is 26 cm
Find the curved surface area:
Curved surface area = πl (R2 + R1)
Curved Surface Area = π(26)(15 + 5) = 1634 cm²
The curved surface area is 1634 cm²
Answer:1634 cm²
Answered by
2
Given:
Height = 24 cm
Radius 1 = 5 cm
Radius 2 = 15 cm
To find:
Curved surface area.
Solution:
By formula,
Curved surface area = π * Length * ( Radius 1 + Radius 2 )
Here,
Length = √ ( Height + ( Radius 2 - Radius 1 )^2 )
Substituting,
√ ( 24 + ( 15 - 5 )^2 )
Length = 11 cm
Hence,
3.14 * 11 * ( 15 + 5 )
Curved surface area = 690 sq.cm
Height = 24 cm
Radius 1 = 5 cm
Radius 2 = 15 cm
To find:
Curved surface area.
Solution:
By formula,
Curved surface area = π * Length * ( Radius 1 + Radius 2 )
Here,
Length = √ ( Height + ( Radius 2 - Radius 1 )^2 )
Substituting,
√ ( 24 + ( 15 - 5 )^2 )
Length = 11 cm
Hence,
3.14 * 11 * ( 15 + 5 )
Curved surface area = 690 sq.cm
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