Question

The radii of circular ends of a bucket of height 24 cm are 15 cm and 5 cm. Find the area of

its curved surface.

Answer 1

Answer:

h= 24cm

r1- radius of upper end=  15cm

r2- radius of lower end = 5cm

curved surface area of frustum=  π (r1+r2)l

now we need to find l

l= $\sqrt{h^{2} } +(r1+r2)^{2}$

l=$\sqrt{24^{2}+10^{2}  }$

l=$\sqrt{676}$

l= 26cm

curved surface are = π (r1+r2)l

=π (15+5) * 26

$\frac{440*26}{7}$

+1634.28 cm$^{2}$

Step-by-step explanation:

Answer 2

Answer:

1634.3 cm² .

Step-by-step explanation:

Let radii be R and r .

It is given R = 15 cm , r = 5 cm and h = 24 cm

We know slant height :

l = [ √ h² + ( R - r )² ]

l = √ 24² + 10²

l = 26 cm .

Now ,

C.S.A. = π ( R + r ) l

= 3.14 × 20 × 26 cm²

= 1634.3 cm² .