Question

the radii of circular ends of a bucket of height 24 cm are15 cm and 5 cm . find the area od its curved surface

Answer 1

Given:

Height = 24 cm

Radius 1 = 5 cm

Radius 2 = 15 cm

To find:

Curved surface area.

Solution:

By formula,

Curved surface area = π * Length * ( Radius 1 + Radius 2 )

Here,

Length = √ ( Height + (  Radius 2 - Radius 1 )^2 )

Substituting,

√ ( 24 + ( 15 - 5 )^2 )

Length = 11 cm

Hence,

3.14 * 11 * ( 15 + 5 )

Curved surface area = 690 sq.cm

Answer 2

Answer:

1634.3 cm² .

Step-by-step explanation:

Let radii be R and r .

It is given R = 15 cm , r = 5 cm and h = 24 cm

We know slant height :

l = [ √ h² + ( R - r )² ]

l = √ 24² + 10²

l = 26 cm .

Now ,

C.S.A. = π ( R + r ) l

= 3.14 × 20 × 26 cm²

= 1634.3 cm² .