Question

the radii of circular ends of a bucket of height 24cm are 15 cm and 5 cm find the area of its curved surface

Answer 1

hey here is ur ans ...

given:-

R = 15 cm
r = 5 cm
h = 24 cm

$l = \sqrt{( {h}^{2} } + (R - r))$
$l = \sqrt{( {24}^{2} } + (15 - 5))$
$l = \sqrt{576 + 10}$
$l = 24.20$
$now$
$c.s.a = \pi \: l(R + r)$
$c.s.a = 22 \div 24.2(15 + 5)$
$c.s.a = 18.18$
$hope \: it \: will \: help \: uh \: .....$
nd plz mark as brainliest ..

Answer 2

Answer:

1634.3 cm² .

Step-by-step explanation:

Let radii be R and r .

It is given R = 15 cm , r = 5 cm and h = 24 cm

We know slant height :

l = [ √ h² + ( R - r )² ]

l = √ 24² + 10²

l = 26 cm .

Now ,

C.S.A. = π ( R + r ) l

= 3.14 × 20 × 26 cm²

= 1634.3 cm² .