Question

the radii of circular ends of a bucket of height 24cm are 15 cm and 5 cm find the area of its curved surface and also its volume

Answer 1

Heya.....❤❤❤

here is ur answer...

Radius of top of the bucket ( R ) = 15 cm.
Radius of bottom of the bucket ( r ) = 5 cm.
Height of the bucket ( H ) = 24 cm.
Therefore,
Slant Height ( L ) = √ ( H )² + ( R - r )²
=> ✓ ( 24)² + ( 15 - 5 )²
=> √576 + (10)²
=> √ 576 + 100
=> √676
=> 26 cm.

• Curved Surface area of bucket = πL ( R + r ) cm².
=> 22/7 × 26 ( 15 + 5 ) cm².

=> ( 22 × 26 ) × 20 / 7 cm².
=> ( 22 × 26 × 20 ) / 7 cm².

=> 1634.28 cm².

hope it helps...

plzz mark me as brainliest my dear !!!

❤❤❤

Answer 2

Answer:

1634.3 cm² .

Step-by-step explanation:

Let radii be R and r .

It is given R = 15 cm , r = 5 cm and h = 24 cm

We know slant height :

l = [ √ h² + ( R - r )² ]

l = √ 24² + 10²

l = 26 cm .

Now ,

C.S.A. = π ( R + r ) l

= 3.14 × 20 × 26 cm²

= 1634.3 cm² .