Question

The radii of circular ends of a solids frustum of a cone are 33cm and 27cm and its slant height is 10cm. Find its total surface area use pie 3.14

Answer 1

Given a frustum ;

• r1 = 33cm
• r2 = 27cm
• l = 10cm

Thus TSA(frustum) ;

• = πl (r1 + r2) + πr1² + πr2²
• = π [ l×(r1 + r2) + r1² + r2² ]
• = π [ 10(33+27) + (33)² + (27)² ]
• = 3.14 [ 10(60) + 1089 + 729 ]
• = 3.14 [ 600 + 1818 ]
• = 3.14 [ 2418 ]
• = 7592.52 cm²

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