Question

The radii of internal and external surfaces of a hollow spherical shell at 3 cm and 5 cm respectively it is melted and recast into a solid cylinder of diameter 14 cm find the height of the cylinder

Answer 1

hope this answer will help you.

Answer 2

Answer:

2.6 cm

Step-by-step explanation:

Outer radius = 5 cm

Inner radius = 3 cm

Volume of sphere = $\frac{4}{3} \pi R^3 -\frac{4}{3} \pi r^3$

                              = $\frac{4}{3} \pi (R^3 -r^3)$

                              = $\frac{4}{3} \times \frac{22}{7} (5^3 -3^3)$

                              = $410.67$

Let the height of cylinder be h

Diameter of cylinder = 14 cm

Radius of cylinder = 14/2 = 7 cm

Volume of cylinder = $\pi r^2 h = \frac{22}{7} \times 7^2 \times h$

Since we are given that it is melted and recast into a solid cylinder.

So, $\frac{22}{7} \times 7^2 \times h=410.67$

$h=2.6$

Hence the height of cylinder is 2.6 cm