Chemistry, asked by Anonymous, 5 months ago

The radii of maximum probability for 3s, 3p and 3d electrons are in
the order:
A) (r max)3d>(max)3p>(max)3s
B) (r max) 3d>(max) 3s>(max)3p
C) (r max) 3s>(max)3p >(max)3d
D) All have same value​

Answers

Answered by akankshappatil16
1

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Answered by AbbasMaths
2

Answer:

Option c is correct

EXplaNAtion :

Hello , we know that the radial wavefunction is directly proportion to it's potential energy of orbital and inversely proportional to it's kinetic quantum state . Ignoring the kinetic energy for the purpose of your question , we can say that energy of electron in 3s is less than energy of electron in 3p and energy of electron in 3p is less than energy of electron in 3d .

We know that , probability of finding electron is maximum in the least energetic quantum state .

Hence , probability ( here radial probability or simply say radii of maximum probability ) is maximum for 3s ( as it is least energetic ) and lesser for 3p and least for 3d ( as it is most energetic in comparison to 3s and 3p ) .

Hence , probability or radial probability or simply radii of maximum probability is maximum for 3s and least for 3d .

CONCEPT :

THE LESS THE ENERGY , THE MORE THE STABILITY .

THE MORE THE STABILITY , THE MORE THE PROBABILITY .

THE MORE THE PROBABILITY , MORE THE RADIUS OF PROBABILITY .

NOW ,

Energy of 3s is least , so it is more stable and hence probability is greater and hence radii of probability is maximum .

Similarily , energy of 3p is in middle and that of 3d is highest that's why their probability or radii of probability is lesser .

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