the radii of the circular ends of a frustum are 6 cm and 14 cm if its slant height is 10 cm then its vertical hight is
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l²={r-R} + h²
10² = (14 - 6) ² + h²
100=8²+h²
100=64+h²
100-64=h²
36=h²
h=√36
h=6
hope this will help you
Answered by
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Answer:
Slant height of a frustum , l = √(R - r)² + h²
l² = (R - r)² + h²
[On squaring both sides]
10² = (14 - 6)² + h²
100 = 8² + h²
100 = 64 + h²
h² = 100 - 64
h² = 36
h = √36
h = 6 cm
Vertical height of the frustum = 6 cm
Hence, the Vertical height of the frustum is 6 cm.
HOPE IT HELPS YOU
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