The radii of the circular ends of a solid frustum of a cone are 18 cm and 12 cm and it’s height is 8 cm. Find its total surface area.
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Answer:
= 2411.52 cm²
Step-by-step explanation:
We have , Height = 8 cm
Base radii , R= 18 cm and r = 12 cm
Also, the slant height
l = √(R -r)² + h²
= √(18-12 )² + 8²
= √ 6² +8²
= √36 + 64
= √100
= 10 cm
Now ,
Total surface area of the solid frustum
π(R+r)l +πR² +πr²
= 3.14 × ( 18 + 12 ) ×10 + 3.14 ×18²+ 3.14 ×12²
= 3.14 × ( 300 + 324 + 144 )
3.14 × 768
= 2411.52 cm²
So the total surface area of the frustum is 2411.52 cm²
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